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Identify radiation patterns using absorbers

Predict and measure how three radioactive sources respond to paper, aluminium and lead.

  • Radioactivity
  • 85 min
  • Upper-secondary physics; approximately ages 16-18
  • English
  • Physics

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Schematic showing a source, a removable absorber, a Geiger-Müller detector and a pulse counter. Change one source or absorber at a time; keep source runs at 20 mm and count for 10 seconds.
Radioactivity · Lab details

Learning Outcomes

  • Predict and compare absorber effects for three sources.

  • Calculate same-source detected-count percentages.

  • Apply a half-value thickness model with explicit assumptions.

Student activity preview

Activity Content

Preview only. In a class session, students can fill in responses and submit their work to the teacher.

1

Predict which radiation will pass through

15 min

You will use a Geiger-Müller detector to count pulses from a radioactive source. Each result is the number of pulses detected during 10 seconds, not a dose measurement. You work remotely and do not handle radioactive material. The lab plays recorded experiments with real apparatus and their measured results. After a run, select or hover over each result bar to read its exact count. Record the numbered results in order, rather than estimating from bar lengths. Copy each completed result into your table before starting another run. If the lab timer runs out, return to this activity and choose Open lab again, then restore your settings and continue from your next empty row.

Source, detector and counter

Schematic showing a source, a removable absorber, a Geiger-Müller detector and a pulse counter. Change one source or absorber at a time; keep source runs at 20 mm and count for 10 seconds.

Change one source or absorber at a time; keep the source-run distance and counting time fixed. Schematic, not to scale.

Alpha radiation consists of helium nuclei; beta-minus radiation consists of electrons; gamma radiation consists of photons. An alpha particle has about 7300 times the mass of an electron. Its short range is associated with dense ionisation, not simply a larger particle size. Penetration depends on radiation type and energy, as well as the material. Paper stops typical alpha particles, while beta and gamma radiation can pass through it. A few millimetres of aluminium strongly reduce many beta components. Gamma radiation is attenuated rather than stopped at one universal thickness.

A half-value thickness is the thickness that halves the transmitted intensity for a specified radiation energy and geometry. In a simplified example with a lead half-value thickness of 12 mm, a 4 mm sheet transmits more than half. This value does not apply to all gamma rays. Lower-energy gamma radiation can have a much smaller half-value thickness, so a few millimetres of lead can attenuate it far more strongly. An absorber result therefore depends on photon energy as well as radiation type.

Use your nuclear-data reference (for example Binas) or the linked Sr-90, Am-241 and Co-60 reference pages to look up the emitted radiation. Remember that a source can have more than one component. Radioactive daughter products can also contribute to a source's detected radiation.

Before measuring, predict roughly what percentage of the unshielded detector count will remain with each absorber. Treat the metal discs as approximately 4 mm thick for this prediction model. Their measured effects will be tested using the lab's named discs.

Predictions before measurement

Fill one row per source before opening the experiment. Percentages are estimates of detected counts relative to the same source with no absorber, not percentages of source activity.

Source Emitted radiation types No absorber (%) Paper (%) Aluminium disc (%) Lead disc (%)
2

Measure all source and absorber combinations

30 min

Open the Radioactivity lab

  1. Open the lab. Measure background in basic mode using the settings below. Then switch to advanced mode for all three sources and four absorber choices.

Available in a class session

After changing a source or absorber, recheck the distance, duration and number of repeats: the lab may reset these controls.

First select basic mode, source None, absorber None, distance 15 mm, duration 10 s, and 3 repeats. Start the experiment and record the three separate results. Leave the absorber out. Calculate the mean background count: add the three counts and divide by three.

Background counts

Fill one row per result. Record pulses in 10 seconds, not pulses per second.

Trial Pulses in 10 s

Calculate the mean background count, B, in pulses per 10 s. Show your calculation.

Switch to advanced mode. Set 20 mm, 10 s, and 1 repeat. For Strontium-90, measure None, Paper, Aluminium Disc and Lead Disc one at a time. Repeat those four settings for Americium-241 and Cobalt-60. Keep distance and counting time fixed.

Record one result for every combination. For each source, calculate

$$\text{percentage remaining}=100\frac{N_{\text{absorber}}}{N_{\text{no absorber}}}.$$

Use the measured counts before background subtraction for this comparison, consistently for every source and absorber. Compare small residual counts with your measured background when interpreting them.

Twelve measurements and their percentages

Complete all 12 rows. The no-absorber result is the denominator only for its own source and has 100%. Retain a measured percentage above 100% if it occurs; do not force it down.

Source Absorber Pulses in 10 s Remaining (%)
3

Compare predictions and detected patterns

15 min

Prediction versus observation

Use one row per source. Name the absorbers and cite measured percentages; use words rather than colour alone to mark agreement.

Source Which predictions agreed? Which differed, and why?

Use the absorber results to describe the dominant detected radiation pattern for each source. Explain why a count close to background does not prove zero transmitted radiation.

4

Apply attenuation models

25 min

Dose and detector counts describe different things. Dose rates may be expressed in microsieverts per hour. As a unit-conversion example, a hypothetical dose budget of 1 mSv spread over 2000 hours corresponds to 0.5 µSv/h. Converting a detector count into a dose requires calibration for the source, detector and geometry.

For this exercise, use 120 detected pulses per 10 s as a classroom comparison target. It is not a dose limit. From your own results, select the least shielding that met this count target for each source. Consider no absorber first, then paper, then the tested metal discs. If both metal discs work, aluminium is less dense than lead; thickness and total mass would still be needed for a real design.

Choose from the tested configurations

Fill all three rows. Use 0 mm for no absorber, "paper; thickness unspecified" for paper, or "4 mm (model)" for a metal disc. If no option meets the target, say so.

Source Chosen absorber (or none) Count and reason Model thickness / qualification

For a simplified lead-thickness calculation, take your measured Co-60 count without an absorber as N. Assume the detected component behaves like a gamma beam with a 12 mm lead half-value thickness, and neglect background in this model. This assumption is for the calculation; it is not a dose calibration.

Using your count N, estimate the lead thickness needed to reach the 120-count target. If N is already at or below 120, enter 0 mm and explain. Otherwise find the number of halvings n in N × (1/2)^n = 120 and multiply by 12 mm. You may use trial values or n = log(N/120)/log(2).

Optional practice: apply the same model to a gamma-only beam giving 480 counts per 10 s. How much lead would bring it to 120?

Shielded viewing windows can let staff observe a patient during medical imaging. Lead glass allows observation through a transparent radiation barrier. Its attenuation depends on glass composition, thickness and photon energy.

State two ways to increase attenuation by lead glass, for the same incident radiation.

Use the following supplied model values for photons of energy 0.662 MeV. For glass thickness d = 1.0 cm, calculate the percentage transmitted:

$$\frac{I_d}{I_0}=\left(\frac12\right)^{d/d_{1/2}},\qquad \text{percentage}=100\left(\frac12\right)^{d/d_{1/2}}.$$

Transmission through 1.0 cm of lead glass

Use d=1.0 cm for all three rows. Calculate with the supplied half-value thicknesses and round the percentage to one decimal place.

PbO concentration (%) Half-value thickness (cm) Transmitted (%)

These calculations compare attenuation models. Detector counts alone cannot establish a person's dose or whether shielding is safe.

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